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Topic: CTS Placement Paper 14 

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thiru
Senior Member Joined: 29Jun2006 Location: India Online Status: Offline Posts: 1 
Topic: CTS Placement Paper 14 Posted: 29Jun2006 at 11:14pm 

* THERE WERE A TOTAL OF 40 QUESTIONS TO BE ANSWERED IN
60 MINUTES.EACH QUESTION CARRIED 1 MARK & 0.25 MARKS WERE DEDUCTED
FOR EVERY WRONG ANSWER.(NEGATIVE MARKING)THERE WERE 5 SECTIONS IN ALL,
EACH HAVING 8
QUESTIONS. * 5 sections * 8 questions each (40 q totally) * 60 minutes * 5 different sets of question papers * 1 Mark each * 0.25 negative marking CTS_BLACK vocabulary,strings,dominoes,functions,coding (each section 8 ques) CTS_BROWN word series,numerical series,functions,figures,verbal (each section 8 ques) CTS_VIOLET functions,strings,bricks,jigsaw puzzle,cryptic clues (each section 8 ques) CTS_RED 1. 8 functions 2. 4 cryptic clues ,4 anagrams 3. 4 tetris figures, 4 bricks 4. 8 strings 5. 4 jigsaw puzzles 4 number series Instructions 1. All answers provided in these sets may not be correct. So Please check. 2. do read old papers. few ques of 2004 came from these old sets INTERVIEW * puzzles * technical BROWN 2004 There were different papers for different sessions. The paper had 5 sections, 5 * 8 = 40 Q's. totally. Section 1 : Functions. Q: 1  8 Certain functions were given & based upon the rules & the choices had to be made based on recursion. This is time consuming, but u can do it. Try to do it at the end. start from the last section. L(x) is a function defined. functions can be defined as L(x)=(a,b,ab) or (a,b,(a,b),(a,(b,b)),a,(b,b)).... two functions were given A(x) & B(x) like if l(x)=(a,b,c) then A(x)=(a) & B(x)=(b,c) i.e., A(x) contains the first element of the function only. & B(x) contains the remaining, except the first element. then the other two functions were defined as C(x) = * if L(x) = () A(x) if L(x) = () & B(x) != () C(B(x)) otherwise D(x) = * if L(x) = () ** if B(x) = () A(x) if L(x) != () & B(x) != () D(D(x)) otherwise now the Questions are, 1 : if L(x) = (a,b,(a,b)) then C(x) is ? (a): a (b): b (c): c (d): none 2 : if L(x) = (a,b,(a,b)) then find D(x) same options as above 3 : if L(x) = (a,b,(a,b),(b,(b))) find C(x) 4 : ~~~~~~~~ find D(x) 5 : if L(x) = (a,(a,b),(a,b,(a,(b))),b) then find c(x) 6 : ~~~~~~~~ find D(x) 7 : if L(x) = (a,b,(a,b)) then find C(D(x)) 8 : ~~~~~~~~ find D(C(x)) Section 2 : Word series Q's : 9  16 This is one of the easiest section. Try to do it at first. if S is a string then p,q,r form the substrings of S. for eg, if S=aaababc & p=aa q=ab r=bc then on applying p>q on S is that ababaabc only the first occurance of S has to be substituted. if there is no substring of p,q,r on s then it should not be substituted. If S=aabbcc, R=ab, Q=bc. Now we define an operator Râ€žÂ» Q when operated on S, R is replaced by Q, provided Q is a subset of S, otherwise R will be unchanged. Given a set S= Â¡KÂ¡KÂ¡K., when Râ€žÂ» Q, P== 672; R, Q â€žÂ» P operated successively on S, what will be new S? There will be 4 = : if s=aaababc & p= aa q=ab r=bc then applying p>q, q>r & r>p will give, (a): aaababc (b): abaabbc (c): abcbaac (d): none of the a,b,c 10: if s=aaababc & p= aa q=ab r=bc then applying q>r & r>p will give, 11: if s=abababc & p= aa q=ab r=bc then applying p>q, q>r & r>p will give, 12: if s=abababc & p= aa q=ab r=bc then applying q>r & r>p will give, 13: if s=aabc & p=aa q=ab r=ac then applying p>q(2) q>r(2) r>p will give, (2) means applying the same thing twice. 14: similiar type of prob. 15: if s=abbabc p=ab q=bb r=bc then to get s=abbabc which one should be applied. (a): p>q,q>r,r>p 16: if s=abbabc p=ab q=bb r=bc then to get s=bbbcbabc which one should be applied. Let us consider a set of strings such as S=aabcab. We now consider two more sets P and Q which also contain strings. An operation P>Q is defined in such a manner that if P is a subset of S, then P is to be replaced by Q. In the following questions, you are given various sets of strings on which you have to perform certain operations as defined above. Choose the correct alternative as your answer. (the below are some ques from old ques papers) 21. Let S=abcabc, P=bc, Q=bb and R=ba. Then P>Q, Q>R, R >P changes S to (A) ............ (B) abcabc (C) ............ (D) none of A,B,C 22. Let S=aabbcc, P=ab, Q=bc and R=cc. Then P>Q, Q>R, R >P changes S to (A) ababab (B) ............ (C) ............ (D) none of A,B,C 23. Let S=bcacbc, P=ac, Q=ca and R=ba. Then P>Q, Q>R, P >R changes S to (A) ............ (B) ............ (C) bcbabc (D) none of A,B,C 24. Let S=caabcb, P=aa, Q=ca and R=bcb. Then P>Q, P>R, R >Q changes S to (A) ............ (B) ............ (C) ............ (D) none of A,B,C Section 3 : numerical series Q's : 17  24 This is little bit tough. proper guesses should be made. find these probs in r.s.aggarval's verbal & non verbal reasoning. 17: 2,20,80,100, ?? (a): 121, (b): 116 (c): (d):none 18: 10,16,2146,2218, ?? like these other series were given. section 3 : series (from other booklet) transformations 17: 1 1 0 2 2 1 1 > 0 0 1 0 0 2 2 1 0 1 1 0 0 1 > 2 1 2 2 1 1 2 then 2 2 1 1 0 1 1 > ???? ans may be 0 0 2 2 1 2 2 18: 1 1 0 0 2 2 > 2 2 0 0 1 1 1 0 1 1 2 1 > 1 2 1 1 0 1 Section 4 : figures 19: ^ ^ ^  > <  >  ^ : ^ :: ^ : ?  > <  <  ans is : ^  < ^  > all probems are very easy.(see cts_old\cts13 file) some are mirror images, some r rotated clockwise/anti Section 5 : Verbal if u have a very good vocab. then this section is managable. two words together forming a compound words were given. the q's contained the second part of the compound word. the first word of the compuond word had to be guessed. then its meaning had to be matched with the choices. if the word is "body" then its meaning of its first part is.. its really tough to guess.. the words were however very simple some words which i can remember are, head, god, (see old papers) like block head main stream star dust Eg: OLD PAPERS (1) (head) (a) purpose (b) man (c)obstacle (d)(ans:c for blockhead) >(2) (dust) (a) container(b)celestial body (c)groom(d)(ans: c for star dust) >(3) (stream )(a) mountain (b) straight (c) (d) (ans:a) >(4) (crash) (a) course (b) stock3 anagram >first find the anagram of the given word & then >choose the meaning of the anagram from the options. >1. latter >rattle 2..spread 3.risque 4.dangled(ansjogged)Â¡K Quest of red set. i) Series Transformation 1) If 102101>210212 then 112112>? a) b) c) d) 2) if 102101> 200111 then 112112>? Again there r 4 choices. 3) If 102101>101201 then 112112>? Again there r 4 choices. Tips:The 1st one all change 0>1, 1>2, 2>1 The 2nd on alternate do not change The 3rd it is just reverse of the original string _______________________________________________________ ii) Target=127: Brick=24,17,13: Operation available= +,/,*, Again there r 4 choices.For ex choice b)20,6,7 Tips:Answer is b one bcos 20*6+7=127.Hence it is the answer Q:1)U HAVE TO MAKE A TARGET =102; THE ANSWER FROM THE OPTION IS (6,17,2,1) 2)TARGET=41;FIVE NO.S WERE GIVEN;25 22 16 5 1 U CAN USE THE NO.S ONLY ONCE&CAN PERFORM OPERATION +,MULTIPLY,,/,()ONCE; OPTIONS WERE; A)25 22 16 5 B)25 22 16 1 C)25 22 5 1 D)25 16 5 1) 4 SUCH QUESTINS ARE THERE. 2)87 3)146 4)127 THERE ARE SOME FIGURATIVE QUESTION;SEE FROM COMPETITION MASTER,I CANT REMEBER THE FIGURE.4 QUESTIONS ARE THERE __________________________________________________ iii) Cryptic Sentence. Form word A sentence is there .a cryptical clue is hidden in the sentence. Find out answer from the opticn. 1)a friend in rome a)aerodrome b)palindine c)palindrome d)condome ans:palindrome 2)Rowed them across a)crosswiz b)acropolis c)acroword d)crossword Ans:crossword/crossover 3)cuticle cutting the filly glass a)cubicle b)uphilly c)cutglass d)cutlass Ans:cutlass 4)hat jumps upward in a water closet a)watch b)witch ans:watch/whatever Tips:The 1st oneJumble out the word SHORE to get the word HORSE and then get the adjective of the word HORSE as TROJAN The 2nd one lips>slip>freudian/french ____________________________________________________________ ___ iv) Anagram noun form the correesponding adjectives There re options. Q:some nouns are jumbled on ,you have to rearrange, look for a suitable adjective: Make a phrase then. 1)shore a)aegean b)Indian c)trojan d)Spartan ans:trojan 2)sire a)dutch b)rome c)herculean d)mercurial ans:mercurial 3)ourcage a)english b)rome c)dutch d)Spartan ans:Spartan 4)lips Again there r 4 choices. Ans:freudian/french ____________________________________________________________ ___ v) Jigsaw puzzle as given in the book by Edgar Thorpe, of TMH Publications ____________________________________________________________ _________ vi) FUNCTIONS same as CTS_BLACK\fun ____________________________________________________________ ________ vii) x , y > strings of G st there is at least one G in x and y xoxy valid xoy>xoxy invalid Find valid & invalid strings ____________________________________________________________ ________ viii)there were a couple of ( seven to be precise)figures ( tetris type if u remember that game) given in the main theme. The 10 questions that followed showed patterns which were formed due to combination of the 7basic figs. NOTE: the intersecting part of the combined fig. always gets subtracted from the total combination Hello Shivesh CTS paper was of diff pattern this time and there were ateast 5 different sets of question papers given to students. Of the type i recvd, as i told there wer 10x4 questions for 60 mins. section: 4) last section( thats bcoz i remeber it well) had meaningful words whose anagrams are nouns and we hav to choose the best adjective from the list to describe this noun: ex: shore ( word given) choices: a) roman b) spanish c) trojan d).... ans: c) trojan shore is anagram(jumbled form of) 'horse' and trojanhorse is the best match 3) there were a couple of ( seven to be precise)figures ( tetris type if u remember that game) given in the main theme. The 10 questions that followed showed patterns which were formed due to combination of the 7basic figs. NOTE: the intersecting part of the combined fig. always gets subtracted from the total combination 2) This section had the funda of xOy where x and y represented strings of Gs . The test was to find the valid or invalid patterns with ref. to the rules 1) L=list of objects ex:L={a,b,c,d} where a,b,c,d are objects P(L) was a function( dont remembr xatly) M(L) was another function defined etc in the following questions P(x) etc were given to be found out. Note : this may take considerable amnt of time. so take intelligent guesses  
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